If begin{bmatrix} x+3 & z+4 & 2y-7 -6 & a-1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Since the given matrices are equal,their corresponding elements must be equal.Comparing the corresponding elements,we get:$x+3 = 0 \implies x = -3

Vedclass · Accepted Answer

$a=-2, b=-7, c=-1, x=-3, y=-5, z=2$

Vedclass · Answer

(D) Since the given matrices are equal,their corresponding elements must be equal.Comparing the corresponding elements,we get:$x+3 = 0 \implies x = -3$$z+4 = 6 \implies z = 2$$2y-7 = 3y-2 \implies 2y-3y = -2+7 \implies -y = 5 \implies y = -5$$a-1 = -3 \implies a = -3+1 \implies a = -2$$0 = 2c+2 \implies 2c = -2 \implies c = -1$$b-3 = 2b+4 \implies b-2b = 4+3 \implies -b = 7 \implies b = -7$Thus,the values are $a=-2, b=-7, c=-1, x=-3, y=-5, z=2$.

If $\begin{bmatrix} x+3 & z+4 & 2y-7 \\ -6 & a-1 & 0 \\ b-3 & -21 & 0 \end{bmatrix} = \begin{bmatrix} 0 & 6 & 3y-2 \\ -6 & -3 & 2c+2 \\ 2b+4 & -21 & 0 \end{bmatrix}$,then find the values of $a, b, c, x, y$ and $z$.

Similar Questions

For matrices $X$ and $Y$,if $X+Y = \begin{bmatrix} 7 & 0 \\ 2 & 5 \end{bmatrix}$ and $X-Y = \begin{bmatrix} 3 & 0 \\ 0 & 3 \end{bmatrix}$,then $2X =$ . . . . . .

The matrix $A = \frac{1}{3}\begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & -2 \\ -2 & 2 & -1 \end{bmatrix}$ is

If $A = \begin{bmatrix} \alpha & \beta \\ \gamma & -\alpha \end{bmatrix}$ is such that $A^{2} = I$,then

If $A$ and $B$ are skew-symmetric matrices of the same order,then $AB - BA$ is a . . . . . . .

If $A$ is an involutory matrix and $I$ is the unit matrix of the same order,then $(I - A)(I + A)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module